Insert
the Missing Character
1. tn lbOPcg';f/
gePsf] vfln :yfgdf_ s'g rflxF ljsNk pko'St x'G5. /f]Hg'xf];\ .
|
A2 |
C4 |
E6 |
|
G3 |
15 |
? |
|
M5 |
O9 |
Q14 |
(A) L10 (B) K15 (C) I15 (D) K8
2. tn lbOPcg';f/
gePsf] -vfnL :yfgdf_ s'g rflxF ljsNk pko'{St x'G5, /f]Hg'xf];\ .
(a) 1 (b) 4 (c) 3 (d) 6
3. tn lbOPsf] gePsf] :yfgdf_ s'g rflxF ljsNk pko'{St x'G5,
/f]Hg'xf];\ .
(a) 18 (b) 12 (c) 9 (d) 6
4. tn lbOPsf]cg';f/
gePsf] -vfnL :yfgdf_ s'g rflxF ljsNk pko'St x'G5 /f]Hg'xf];\ .
(a) 25 (b) 37 (c) 41 (d) 47
5. tn lbOPcg';f/
gePsf] -vfnL :yfgdf_ s'g rflxF ljsNk pko'{St x'G5 , /f]Hg'xf];\ .
(a) 45 (b) 41 (c) 32 (d) 40
6. tn lbOPcg';f/
gePsf] -vfnL :yfgdf_ s'g rflxF ljsNk pko'{St x'G5, /f]Hg'xf];\ .
(a) 115 (b) 130 (c) 35 (d) 140
7. tn lbOPcg';f/
gePsf] -vfnL :yfgdf_ s'g rflxF ljsNk pko'{St x'G5 , /f]Hg'xf];\ .
(a) 92 (b) 72 (c) 62 (d) 99
8. tn lbOPcg';f/
gePsf] -vfnL :yfgdf_ s'g rflxF ljsNk pko'{St x'G5, /f]Hg'xf];\ .
|
18 |
24 |
32 |
|
12 |
14 |
16 |
|
3 |
? |
4 |
|
72 |
112 |
128 |
(a) 2 (b) 3 (c) 4 (d) 5
9. tn lbOPcg';f/ gePsf] -vfnL :yfgdf_ s'g rflxF ljsNk pko'{St x'G5, /f]Hg'xf];\ .
(a) 36 (b) 48 (c) 38 (d) 30
10. tn lbOPcg';f/
gePsf] -vfnL :yfgdf_ s'g rflxF ljsNk pko'{St x'G5, /f]Hg'xf];\ .
(a) 41 (b) 64 (c) 35 (d) 61
11. tn lbOPcg';f/ gePsf] –vfnL :yfgdf
s'g rflxF ljsNk pko'{St x'G5,
(a) 13 (b) 14 (c) 12 (d) 15
12. tn lbOPcg';f/
gePsf] –vfnL :yfgdf 'sg rflxF ljsNk pko'{St x'G5, /f]Hg'xf];
(a) 262 (b)622 (c) 631 (d) 824
13. tn lbOPcg';f/
gePsf] –vfnL :yfgdf s'g rflxF ljsNk pko'{St x'G5 , /f]Hg'xf];\
(a) 45 (b) 29 (c) 39 (d) 37
14. tn lbOPcg';f/
gePsf] -vfnL :yfgdf s'g rflxF ljsNk pko'{St x'G5 , /f]Hg'xf];\
(a) 184 (b) 210 (c) 241 (d) 425
15. tn lbOPcg';f/ gePsf] –vfnL :yfgdf
s'g rflxF ljsNk pko'{St x'G5, /f]Hg'xf];\
|
2 |
4 |
0 |
|
12 |
4 |
3 |
|
1 |
3 |
36 |
|
? |
91 |
|
(a) 15 (b) 19 (c) 20 (18)
16. tn lbOPcg';f/ gePsf] –vfnL :yfgdf s'g rflxF ljsNk pko'{St x'G5 , /f]Hg'xf];\
(a) 11 (b) 14 (c) 10 (d) 12
17. tn lbOPcg';f/ gePsf] –vfnL :yfgdf
s'g rflxF ljsNk pko'{St x'G5 , /f]Hg'xf];\
(a) 64 (b) 144 (c) 169 (d) 25
18. tn lbOPcg';f/ gePsf] –vfnL :yfgdf
s'g rflxF ljsNk pko'{St x'G5 , /f]Hg'xf];\
(a) 8 (b) 12 (c) 16 (d) 20
19. tn lbOPcg';f/ gePsf] –vfnL :yfgdf
s'g rflxF ljsNk pko'{St x'G5 , /f]Hg'xf];\
.
|
7 |
4 |
5 |
|
8 |
7 |
6 |
|
3 |
3 |
? |
|
29 |
19 |
31 |
(a) 3 (b) 5 (c) 4 (d) 6
20. tn lbOPcg';f/ gePsf] -vfnL :yfgdf
s'g rflxF ljsNk pko'{St x'G5 , /f]Hg'xf];\
.
|
4 |
5 |
6 |
|
2 |
3 |
7 |
|
1 |
8 |
3 |
|
21 |
98 |
? |
(a) 94 (b) 76
(c) 16 (d) 73
|
Answer
with Explanation |
||
|
1. |
(d) |
2 + 4 – 6 5 + 9 – 14 Similarly, 3 + 5
= 8 K8
|
|
2. |
(d) |
(5 + 4 +
7) /2 = 8 (6 + 9 +
5)/2 = 10 (3 + 7 + 2)/ 2 = 6 |
|
3. |
(c) |
(12 + 18
+ 30)10 = 6 (16 + 24+ 40) / 10 = 8 (Similarly, (45 + 18 + 27) /
10 = 9. |
|
4. |
(c) |
(5 ×3) +
4 = 19 and (6 × 4) + 5 = 29 Therfore, (7 × 5) + 6 |
|
5. |
(a) |
(15 × 2 –
3) = 27, (31 × 2 – 6) = 56 and
(45 × 2 – 9) = 81 |
|
6. |
(b) |
(5 × 6 ×
8) + (7 × 4 × 9) = 492 and
(7 × 5 × 4) + (6 × 8 × 9) = 572 Therefore (4 × 3× 5) + 7 × 2 × 5)
= 130 |
|
7. |
(d) |
(21 + 31 – 52 (and (39 + 46 =85 Therefore,
16 + 83 = 99, |
|
8. |
(b) |
(18 × 12)/ 3 = 72 and (32 × 14) = 128 Therefore
(24 × 14)/? = 112 (336/?) = 112 (336/112) = 3 |
|
9. |
(c) |
(0 + 2 + 6 + 4) – 2 = 10 and
(6 + 2 + 10 + 8) – 2 =24 Therefore,
(4 + 14 + 12 + 10) – 2 = 38. |
|
10. |
(b) |
(a)3 = 1, (2)3 = 8,
(3)3 = 27 Therefore, (4)3
= 64. |
|
11. |
(d) |
Sum of
number n lower half of the circle = 11 + 9 + 3 + 7 = 30 Sum of
numbers n upper half of the circle = ? + 4 + 5 + 6 = ? + 15 Upper
half – Lower half 30 = ? +
15 ?
= 30 – 15 ? = 15. Therefore,
15 s the answer |
|
12. |
(b) |
915 – 364
= 551 and 7899 – 543 = 246 S.U lary,
863 – 241 |
|
13. |
(c) |
 |
|
14. |
(a) |
(12)2 – (8)2 = 80 and (16)2 –
(7)2 = 207 Therefore (25)2
– (21)2 = 184 |
|
15. |
(d) |
(2)3
+ (1)3 + (3)3 = 36 and (0)3 + (4)3 + (3)3
= 91 Therefore,
(4)3 + (2)3 + (1)3 = 73 |
|
16. |
(a) |
(15 – 12) + (10 – 9) = 4 (28 – 12) + (16 – 20) = 1 Salary,
(23 – 11) + (15 – 16) = 11 |
|
17. |
(a) |
The
numbers are squared n ascend ng order in first circle (3)2
= 9 (4)2=
16 (5)2
= 25 (6)2=
36 In second circle, (4)2
= 16 (5)2 =
25 (6)2
= 36 (7)2 =
49 In thrd circle, (6)2
= 36 (8)2 =
64 (9)2
= 81 |
|
18. |
(c) |
(4 × 6) `¸ 3 = 8 (6 × 10) ¸ 5 = 12
(4 × 8) ¸ 2 = 16 |
|
19. |
(b) |
(7 × 3) +
8 = 29 (4 × 3) + 7
= 19 (5 ×?) + 6 = 31 ? = 5 |
|
20. |
(a) |
(4)2 + (2)2 + (1)2
=21 and (5)2 +
(3)2 + (8)2 = 98 Therefore
(6)2 + (7)2 + (3)2 = 94. |